Drop down values redisplay

[Tikila]

I have this
<form name="myform" action="action.php" method="post">
<select name="myoptions">
<option value="option1">option1</option>
<option value="option2">option2</option>
<option value="option3">option3</option>
<option value="option4">option4</option>
<option value="option5">option5</option>
</select>
</form>

And i want to apply the following code on it(gratefully provided by Byron3@earthlink),
how would i integrate this?

function DisplayMenuChoices( $selected ="") {
$list = array( "option1",
"option2",
"option3",
"option4",
"option5"
);
echo "<select name='myoptions '>\n";
foreach ( $list as $name ) {
if ( $name == $selected ){
echo " <option selected='selected'>$name</option>\n";
} else {
echo " <option>" .$name. "</option>\n";
}
}
echo "</select>\n"; // End select list
}

I would prefer this method,if it does not generate duplicates
Appreciate your support

[byron3@earthlink]

/* Take the function and place it in php tags <?php Function_goes_here ?> */

<form name="myform" action="action.php" method="post">
<? DisplayMenuChoices(); ?> // When you get ready to display this with a user selected value. Place the value in the ( $user_selected_value )
</form>

Does this head you in the right direction?

[Tikila]

When i replace
<select name="myoptions">
<option value="option1">option1</option>
<option value="option2">option2</option>
<option value="option3">option3</option>
<option value="option4">option4</option>
<option value="option5">option5</option>
</select>
in the redisplay page,the menu is not ouputt

[Tikila]

Has anyone implemented this successfully before?
I'd appreciate a working example

[byron3@earthlink]

Tikila post me your redisplay code.
Use the php block tags to enclose your code, click on the "Go Advanced" button below. The icon next to the box that has syntax in it will put a set of php block tags on this page. Just roll your mouse over it and the tool tip will read "Wrap [php] tags around selected text". Click on that icon and you will a pair of "[ ]" "[ ]" with php in the first set of brackets and /php in the second set of brackets, insert your code block between the two.

[thenk83]

Try this Tikila

<? 
function DisplayMenuChoices( $selected ="") {
$list = array( "option1", "option2", "option3", "option4", "option5");
echo "<select name='myoptions '>\n";
foreach ( $list as $name ) {
if ( $name == $selected ){
echo " <option selected='selected'>$name</option>\n";
} else {
echo " <option>" .$name. "</option>\n";
}
}
echo "</select>\n"; // End select list
}

// YOU NEED THE CODE BELOW TO DISPLAY THE DROP MENU
DisplayMenuChoices();
?>

[Tikila]

Thank you guys for your help
As Thenk83 emphasized at the bottom of his code,i was missing the DisplayMenuChoices(); at the bottom to ouput the menu.Now that i have the menu displayed when i select,say option 3 in page 1,it does not redisplay as option3 in page2(redisplaying page).
I must be missing something then.
The function that i currently use works fine,except it duplicates entries which is confusing to users,i dont like it.
Here's my current function:

<select name="myoptions">
<?php if(isset($_POST['myoptions'])) {
?>
<option value="<?php echo ($_POST['myoptions']); ?>" selected><?php echo ($_POST['myoptions']); ?></option>
<?php
}
?>
<option value="option1">option1</option>
<option value="option2">option2</option>
<option value="option3">option3</option>
<option value="option4">option4</option>
<option value="option5">option5</option>
</select>

[thenk83]

You missing name="myoptions" on each <option></option> tag.

should be..
<option name="myoptions" value="option3">option3</option>.

You're calling a variable ($_POST['myoptions']) that doesn't exist.

[Tikila]

Oh,am sorry,but you're referring to my current function that i dont intend to use because of the duplicate thing.
I want to use Byron code but am unable to get a selected option redisplay on another page.I have the code set as exactly you put above.

[thenk83]

so then.. i assume for each option value it looks like this:

<option name="option3" value="anotherpage?myoptions=option3">option3</option>..
thats the only way i know it will work with calling $_POST['myoptions']..

maybe i'm still not understanding.. sorry

[Tikila]

so then.. i assume for each option value it looks like this:

<option name="option3" value="anotherpage?myoptions=option3">option3</option>..
thats the only way i know it will work with calling $_POST['myoptions']..

maybe i'm still not understanding.. sorry

Ok,there is no $_POST['myoptions'] in the function DisplayMenuChoices Byron suggested above,but i cannot get a selected option to redisplay as default in the following page(a confirmation page that serves as a last chance for the user to check their info before final submission).
As for my current function that has the $_POST['myoptions'] it does work the way i coded it above redisplaying exactly what was selected previously(even with no <option name="myoptions"> that you noted,except i end up with duplicate entries in the drop down menu.

[thenk83]

actually no i was wrong.... you dont need name in the <option></option>. I dont know what I'm thinking. I don't see why its giving duplicate entries..

[byron3@earthlink]

<select name="myoptions">
<?php if(isset($_POST['myoptions'])) {
?>
<option value="<?php echo ($_POST['myoptions']); ?>" selected><?php echo ($_POST['myoptions']); ?></option>
<?php
}
?>
<option value="option1">option1</option>
<option value="option2">option2</option>
<option value="option3">option3</option>
<option value="option4">option4</option>
<option value="option5">option5</option>
</select>

/* Tikila lets modify your code block to this */

<?php
if ( isset($_POST['myoptions'] )) { // Does the post variable myoption contain data ?
    $tmp = $_POST['myoptions']; // Yes , put value in variable selected
} else {
    $tmp = ""; // No, put null value in variable
} // End if

DisplayMenuChoices( $tmp ); // Display the menu, the correct choice will be selected
?>