Hello,

I get the error:
Notice: Undefined index: other

the line with this error has the code:
$a = $_POST['other'];


I tried to fix the code by doing this:
if (isset($_POST['other'])){
$a = $_POST['other'];
}


but this just gave me a new error:
Notice: Undefined variable: a

I tried to define the variable:
if (isset($_POST['other'])){
var $a;
$a = $_POST['other'];
}


but then a fatal error occurs (unexpected T_VAR )

Can anyone suggest how I get rid of the 'undefined index' error properly (rather than just hiding it) so that new errors don't keep popping up?