trying to echo image id

[wazo]

Hi guys

trying to echo the id which is stored in $field6

echo"<img src=image.php?id='$field6'>"; 

but when the x image displays and i press properties it says that there is no id being called

many thanks in advance for your help

[IP-Dope]

Hi guys

trying to echo the id which is stored in $field6

echo"<img src=image.php?id='$field6'>"; 

but when the x image displays and i press properties it says that there is no id being called

many thanks in advance for your help

Try this:

echo "<img src=\"image.php?id={$field6}\" alt=\"\" />"; 

Hope this helps.

Cheers,
Pepe

[wazo]

that didnt work

[IP-Dope]

Well, that should pass $field6 to your image.php file. What's in your image.php file? Did you try to

echo $_GET['id']; 

? What's the value of $field6?

[wazo]

$field6 is the id of the image

if i write it like this

echo "<img src=image.php?id=18>";

then it works fine

but I need to replace the value of 18 with field6

how would line be written with echo $_GET['id'];

[IP-Dope]

Alternatively, you could try

echo '<img src="image.php?id='.$field6.'" alt="" />'; 

but that shouldn't make much of a difference.
Are you sure $field6 is set properly?
Above the echo line, add

$field6 = '18'; 

If that works then something goes wrong when assigning the value to $field6..

[Chousho]

Are you calling this from a database or is this a variable set earlier in the page?

In any case, when using a variable, you have to echo/print it:

echo "<img src=\"image.php?id=$field\" alt=\"\" />";

// Or

echo "<img src=\"image.php?id=".$field."\" alt=\"\" />"; 

[wazo]

Fixed it guys

thanks

[Chousho]

very strange as now the x box has disappeared

That's why I'd get a Playstation 3, not an XBox ;D

Try editing the alt tag to say "image 1" or something.

Is the $field variable a string giving a location? Is it an absolute path (www.domain.com/image.jpg) or a relative one (img/blah.jpg)?