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May 9, 2007, 01:59 #1
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Regular expression with opening & closing tags
The regular expression must take the text example below, remove all the <a name> (opening and closing) tags and only leave <i><b>1 VISION AND MISSION</b></i> (ignore the <b> and <i> for now, I have an expression to replace them with <strong> and <em>)
<a name="_Toc153934773"></a><a name="_Toc121546821"></a><a name="_Toc121541109"><i><b>1 VISION AND MISSION</b></i></a>
If I use the following expression, it removes the first 2 tag sets, ie the ones without any text enclosed, but leaves the third one intact
ie. returns <a name="_Toc121541109"><i><b>1 VISION AND MISSION</b></i></a>
code = code.replace(/<a name=[^>]*>([^<\/a>])<\/a>/gi,"$1");
The first and the last parts are fine (green), it's the red bit I'm struggling with
the red part is supposed to find all text excluding </a> and store it in a backreference, which is then used as the replacement string $1.
To group <\/a> in order to treat it it as a phrase, you should enclose it in (), and that's where my confusion comes in, when does it treat it as a backreference and when as a grouping clause?
Your help is appreciated