Some Help required about date and Time

[zeeshanhashmi]

Hi

Please note that in my HTML form i have 6 text boxes, that is

Day1, Month1, Year1,
and
Day2, Month2, Year2,

both the sets are used to get the Date of birth from the user.

Now in PHP i want to do following :

1 - i want to concatinate the Day,Month,Year to create a date object.
2 - When both the sets are concatinated to represent 2 different dates, i want to determint the younger of them .
3 - I want to determine the age in years and in months from both the dates.

Please guide me in this regards !!

Zeeshan

[World Wide Weird]

There is no date object per se in PHP. You can get a Unix timestamp integer like this:

$date = mktime(0,0,0,$month,$day,$year); 

The larger of two such integers will be the younger one. Subtract the smaller number from the larger number to get the difference. Each integer represents a certain number of seconds, so you will have to do some math to convert the difference to months and years.

[zeeshanhashmi]

ok this way how can i get the age of both the persons in years ?
moreover, how can i get their DOB ? can i do this

echo date('d-m-Y',$date);

please guide

[mmarif4u]

Salam,
I am not clear about ur post...
R U recieve the day, month, year from select boxes seperatly.

[zeeshanhashmi]

Walaykum assallam WarehmatAllah

I have text boxes for the Day, Month and Year. User put the day, month and year by typing.

Now i want to convert the THREE textbox values to form a PHP date. And then i want to know the User age in months and years.

Please guide.

[mmarif4u]

Ok 1st of all nice to meet u on sitepoint.
I will suggest u to make select boxes for day, month, and year.

Then use php varaibles for to make a date.
How let me explain...

day (textbox or select box) from html form

$day=htmlentities($_POST['day']);
$month=htmlentities($_POST['month']);
$year=htmlentities($_POST['year']); 

I use htmlentities, this is when u use textboxes not for select boxes,
This is for security purpose that a user cannot enter some specail characters.
like (./><~!).hope u got it.
If u want to use mysql db then for db use like this.

$day=mysql_real_escape_string($_POST['day']); 

And so on for month and year.

After all of that now u have to make date in from above $day,$month,$year.

make a new variable in php under the above variables:

$date=$year"-"$month"-"$day; 

Thats all test it and then reply me either it works or not.

[LJK]

Hi -
I'm a newb. w/ php, so perhaps am off -
but was wondering if this would work:

$day1=$_POST ['year1'];
$month1=$_POST ['year1'];
$year1=$_POST ['year1'];
$day2=$_POST ['year2'];
$month2=$_POST ['year2'];
$year2=$_POST ['year2']; 

then concat. with something like:

$dob1 = $day1.'-';
$dob1 .= $month1.'-';
$dob1 .= $year1;
//repeat as $dob2 for the 2's... 

And then do your comparison using $dob1 and $dob2.

Good luck,
El

[mmarif4u]

Oh sorry i forgot :

Try this:

$date=$year."-".$month."-".$day; 

[zeeshanhashmi]

i have already done that all.

But that will concat the TEXTs not converthing them to DATE. I want that to be converted in to date, so that i can perform some other Date operations on it.

[Ernie1]

something like this:

$date=strtotime("04-06-2005"); //example date
echo date('d',$date)."-".date('m',$date)."-".date('Y',$date); 

[zeeshanhashmi]

Hi

thanks for all the replys. Please note that when the user enter theyr date of birth by filing the DAY / MONTH and YEAR text boxes. Then i want to know when its next Birthday is comming ? is it in next 60 days, is it in next 180 days ? or it is next year ? this is waht i want to achieve.

Please help.

[zeeshanhashmi]

is there any one who may figure out the solution ?

[Ernie1]

Countdown timer

function time_until($event, $day, $month, $year = "unset", $min = 0, $hour = 0, $sec = 0){
    
    /**
     * The above prints the time until a given date.  
     * This can calculate to any time of day.
     */
    
    /**
     * If you didn't put a year above ($year = "unset"), assume it's the current year
     */
    
     if ($year == "unset")
         $year = date("Y");
    
     $left = mktime($sec, $min, $hour, $month, $day, $year) - mktime();
    
    /**
     * Lets assum that this is an annual event such as a Birthday and that 
     * it will happen again next year. This starts the counter over again after 
     * the event takes place.
     */
    
     if (0 > $left)
         $left = mktime($sec, $min, $hour, $month, $day, $year + 1) - mktime();
    
    /**
     * If there is no time left on the counter (the day has come) 
     * Change the "My" if you want, but leave the $event for the event name 
     * This is set so it will say: "My Birthday"
     */
    
     if ($left == 0)
         return "My $event";
    
     $time = array(
        "year" => 31449600,
         "week" => 604800,
         "day" => 86400,
         "hour" => 3600,
         "minute" => 60,
         "second" => 1);
    
     $ret_str = "There ";
    
     while(list($span, $scale) = each($time)){
         $chunk = floor($left / $scale);
         $left = $left % $scale;
        
         if ($chunk != 0):
            
            /**
             * if there is more than one day left, have are, for 1 day have is
             */
            
             $p1 = ($chunk == 1) ? "is" : "are";
        
         if ($chunk > 1)
             $span = "${span}s";
        
         $sep = ($left == 0) ? " and " : ", ";
        
         $ret_str .= ((!ereg("[0-9]", "$ret_str")) ? $p1 : $sep) .
         " $chunk $span";
        
         endif;
        
         }
    
     return $ret_str . " until my ${event}.";
    
    }
    
 $birthday="1965-04-05"; //my birthday ;-)
 $date= explode('-', $birthday);
 /**
 *("Event", day of month, month);
 */
echo time_until("Birthday", $date[2], $date[1]);