instance variables and accessors question...

[Skyblaze]

I have a doubt; if i had:

class Foo

  def first_instance_method
    @instance_variable_foo = 2
  end

  def second_instance_method
    @instance_variable_foo = 10
  end

  def foo_variable_accessor_method
    @instance_variable_foo
  end

end

...the accessor method which "@instance_variable_foo" print out of the two instance methods?

[satishtalim]

I have a doubt; if i had:

class Foo

  def first_instance_method
    @instance_variable_foo = 2
  end

  def second_instance_method
    @instance_variable_foo = 10
  end

  def foo_variable_accessor_method
    @instance_variable_foo
  end

end

...the accessor method which "@instance_variable_foo" print out of the two instance methods?

I am not quite sure what your doubt is:
In case you add the following code to your class -

f = Foo.new
puts f.first_instance_method
puts f.second_instance_method
puts f.foo_variable_accessor_method

It prints out:

>ruby tmp.rb
2
10
10
>Exit code: 0

For the object f above there's only one instance of the variable @instance_variable_foo

[Skyblaze]

I am not quite sure what your doubt is:
In case you add the following code to your class -

f = Foo.new
puts f.first_instance_method
puts f.second_instance_method
puts f.foo_variable_accessor_method

It prints out:

>ruby tmp.rb
2
10
10
>Exit code: 0

For the object f above there's only one instance of the variable @instance_variable_foo

why it prints out two times ten instead two times two?

[Fenrir2]

There is only one variable. It's like this:

puts a = 2  # sets a to 2 and prints 2
puts a = 10 # sets a to 10 and prints 10
puts a # prints a (which is 10 now)

f = Foo.new
puts f.first_instance_method # sets the variable to 2 and returns 2
puts f.second_instance_method # sets the *same* variable to 10 and returns 10
puts f.foo_variable_accessor_method # returns the instance variable (which is 10 now)

[Skyblaze]

There is only one variable. It's like this:

puts a = 2  # sets a to 2 and prints 2
puts a = 10 # sets a to 10 and prints 10
puts a # prints a (which is 10 now)

f = Foo.new
puts f.first_instance_method # sets the variable to 2 and returns 2
puts f.second_instance_method # sets the *same* variable to 10 and returns 10
puts f.foo_variable_accessor_method # returns the instance variable (which is 10 now)

ok, so the last called method is responsible for the actual value of that variable right?