Date Variables?

[Rhaegar]

Is there anyway in php to figure out the number of days between two dates? Given two dates by the user in the format YYYY-MM-DD can I find the number of days between the two. I can change the format if I have too.

[cupid]

This is one solution, if date format is kept consistently at YYYY-MM-DD.

<?php

$date0 = "2002-11-25";   //date begin
$date1 = "2003-01-09";   //date end

$dates0 = explode("-",$date0);
$dates1 = explode("-",$date1);

//Note: 86400 seconds in 1 day
echo round((mktime(0,0,0,$dates1[1],$dates1[2],$dates1[0])-mktime(0,0,0,$dates0[1],$dates0[2],$dates0[0]))/86400)." days";

?>

[hadley]

Here's a couple of useful date functions I got from somewhere - however, both use the php date timestamp.

function dateAdd ($interval,  $number, $date) {
    $date_time_array  = getdate($date);
      
    $hours =  $date_time_array["hours"];
    $minutes =  $date_time_array["minutes"];
    $seconds =    $date_time_array["seconds"];
    $month =    $date_time_array["mon"];
    $day =    $date_time_array["mday"];
    $year    =     $date_time_array["year"];

    switch ($interval) {
        case "yyyy":
            $year    +=$number;
            break;                
        case "q":
            $month +=($number*3);
            break;                
        case "m":
            $month +=$number;
            break;                
        case "y":
        case "d":
        case "w":
            $day+=$number;
            break;                
        case "ww":
            $day+=($number*7);
            break;                
        case "h":
            $hours+=$number;
            break;                
        case "n":
            $minutes+=$number;
            break;                
        case "s":
            $seconds+=$number;
            break;                
    }         
    $timestamp =    mktime($hours    ,$minutes, $seconds,$month ,$day,    $year);
    return $timestamp;
}

function dateDiff ($interval, $date1,$date2) {
  // get the number of seconds between the two dates
    $timedifference =  $date2 - $date1;
    
  switch ($interval) {
    case "w":
      $retval  = $timedifference / 604800;
      break;
    case "d":
      $retval  = $timedifference / 86400;
      break;
    case "h":
      $retval = $timedifference / 3600;
      break;        
    case "n":
      $retval  = $timedifference / 60;
      break;        
    case "s":
      $retval  = $timedifference;
      break;        
  } 

$retval = floor($retval);
return $retval;
}

?>