PHP Code:
<?
$connection = mysql_connect("myhost", "user", "") or die("Couldn't connect to server.");
$db = mysql_select_db("mydb", $connection) or die("Couldn't select database.");
                                   // could do all on one page by setting !isset to $cat_id
$sql*=*"SELECT***FROM*category*WHERE*parent_id IS NULL";
$result*=*mysql_query($sql) or die ("cannot execute query");
while*(*$row*=*mysql_fetch_array($result)*{
echo ("<html><head></head><body><p><a href=\"disp_subcats?parent_id=".$row['cat_id']."\">".$row['name']."</a></p>");
}
include("footer.php");
?>

getting an error on line 5 (the $sql bit). Can anyone see where my ignorance lies? (don't laugh )