simple problem????

[MPK]

Ok! I got 5 variables, $option1, $option2 etc.. I want to do the same sort of thing on each variable, so thought I would use a while loop. So I tried the following.

while ($count <= 5) {
$optionx = '$option' . $count;

if ($optionx == true) {
// code
}
$count++;
}

However while wondering why this didn't work I put
echo "OptionX = $optionx"; and it printed OptionX = $option1 not the value of option1 which I was hoping.

Hopefully you can see what I want to do and what the problem is, any help / tips would appricated.

[aspen]

You're trying to rename a variable name... you need to use variable variables.

On the other hand are you familiar with the array_walk function? its very useful in these situations.

You can simply put all your options in an array.

Then

function function_name($element){
//Do whatever with element
}

array_walk($option_array, 'function_name');

array_walk will pass each value in the array to the function, so you can do the same thing on each element no problem.

[aspen]

oh... here is more info on variable variables

http://www.php.net/manual/phpfi2.php#varvars

[Stallion]

As aspen said, variable variables is what you need.

for ($i=1;$i<=5;$i++) // will use 5 variables, from 1-5
${"option".($i-1)} = ${"option$i"}; // $option0 = $option1; $option1 = $option2; etc....