Image display script

[Theiggsta]

I was always puzzled at how some sites can use one script as the src for the images, and it will pull it from a database of information on what file it needs and how to access it.

what my question is how you can do this

<img src="image.php?imgid=29023"> 

and have it return and image in a certain folder, but still hav that if you view the source. I have fried fopen, but that doesnt work. I havent found much on the subject, so I thought I would ask. If you want to see the code for finding it, here is a sample.

if ( isset($imgid) ) {
    $imginfos=$DBO->query_first("SELECT sku FROM items WHERE sku='$imgid'");
    $imginfo=$imginfos[sku];
    // readfile("$imginfo");
    @fopen ("/home/store/stock/".$imginfo.".gif", "rb");
} else {
    @fopen ("/home/store/stock/blank.gif", "rb");
} 

as you can see I also tried readfile, but I am not too sure on how to use it.

[Theiggsta]

I tried out readfile() and used the fopen parameters, aparently it worked!

great how you figure things out like that