Help needed with OOP

[greg76]

Aloha,

I started learning OOP and for my first class I wanted to build 'form generator'. Class worked beautifully, so I wanted to make it more dynamic.

Story:
while the user hits 'submit' button, I want to display the form AGAIN, filled with whatever user entered (confirmation). Without class I do thing like that by checking hidden file and if it exists, I just print values for each field, eg.

<input type="text" name="name" class="form1" value="<? if ($go == '1') { echo $name; } ?>

now, I wanted to do the same inside my class, but I don't know how to make the script read that hidden var.

Part of my class's code - submit function, where i put hidden var the way I would do without any class:

    function f_submit($name="Submit", $value="") {
        echo "<br><br>";

        echo "<input type=\"submit\"";
        echo " name=\"" . str_replace(" ", "_", $name) . "\"";

            if ($value){
                echo " value=\"" .$value. "\"";
            } else {
                echo " value=\"" .$name. "\"";
            }
        echo ">";
        echo "<input type=\"hidden\" name=\"go\" value=\"1\">";
    } 

and then in my other functions which print proper fields I check if the $go has a value, and if it has - print fields value.

    function f_input($title, $name, $value="") {
        echo "<br><br>";
        echo $title . "<br>";
        echo "<input type=\"text\"";

        if (!$name){
            $name = str_replace(" ", "_", $title);
            }

        echo " name=\"" .$name. "\"";
        echo " value=\""; 
            if ($go == '1') echo $name;
        echo "\"";
      } 

and here this IF condition [if ($go == '1')] simply does not work. How can I make it work?

Actually, this leads to second problem. While contruction

<input type="text" name="name" class="form1" value="<? if ($go == '1') { echo $name; } ?>

allowed me to print actual value of $name entered by user, the contruction for class will take a value for $name from funtion's argument, NOT from whatever user entered.

How can I bypass that and make a function and class working?


Thank you a lot for any help.
G.

[sweatje]

$go does not appear to be set anywhere. Do you mean $_POST['go']?

[greg76]

Hey Sweatje,

I tried $_POST['go'] before without results. Maybe I put that with some error, because I tried it again few secods ago and it beautifully worked

Thank you!



The IF condition worked, but as I expected it printed function's argument instead of the string I typed in the input field.

    function f_input($title, $name, $value="") {
        echo "<br><br>";
        echo $title . "<br>";
        echo "<input type=\"text\"";

        if (!$name){
            $name = str_replace(" ", "_", $title);
            }

        echo " name=\"" .$name. "\"";
        echo " value=\""; 
            if ($_POST['go'] == '1') echo $name;
        echo "\"";
      } 

while creating a form and typing, eg.

$form = new make_form();
$form->f_input("Enter something", "", ""); 

it produces:
Enter something<br><input type="text" name="Enter_something" value="">

and then, after hitting 'submit', the class prints 'Enter_something' in that input field as a value, not what I had typed there.

Of course, beacuse $name is both function argument and input field name. But, how can I print input field's value, not argument's value?

Thanks.
G.

[greg76]

I fixed that by adding another $_POST value.

    function f_input($title, $name, $value="") {
        echo "<br><br>";
        echo $title . "<br>";
        echo "<input type=\"text\"";

        if (!$name){
            $name = str_replace(" ", "_", $title);
            }

        echo " name=\"" .$name. "\"";
        echo " value=\""; 
            if ($_POST['go'] == '1') echo $_POST[$name]; else echo $value;
        echo "\"";
      } 

and it works now as it should.

Thanks Sweatje for a hint!


G.