How do you surpress the following PHP Warning:
Undefined variable: submitjoke in C:\Inetpub\wwwroot/php/deletejokes.php on line xx
Basically, there is an HTML form on the .php page but through the use of the PHP if: else: contol structure the PHP variable $submitjoke created by the NAME="submitjoke" form attribute is not processed at that time leading to the undefined variable.
It sounds like PHP is running in 'safe mode' of some sort - do you have control over the php.ini file? If so post it on here (or private message the file to me) and I'll point out what's wrong with it.
Can you post the code? Is this from Kevin Yank's tutorial? I did Kev's tutorial earlier this year - and came accross some bugs that occured because of language changes between PHP3 (which he wrote the tutorial in) and PHP4.
For example: if ("SUBMIT" == $submitjoke)
Causes an error in PHP4 if $submitjoke is not set
but: if ($submitjoke == "SUBMIT")
Works regardless of whether $submitjoke existed prior to the conditioinal statement!