cleaning out a directory

[raphaeld]

Another easy one, but I'm learning:

This is my array:

print_r ($the_array); 

and it outputs:
Array ( [0] => bya_img.inc.php [1] => captions.inc.php [2] => pic1.jpg [3] => pic2.jpg [4] => pic3.jpg [5] => pic4.jpg [6] => pic5.jpg [7] => pic6.jpg [8] => pic7.jpg [9] => Thumbs.db )

How can i clean out the array so there's only the images (jpg)?

thanks

[gavwvin]

foreach($the_array as $key=>$file)
{
  //checks $file that it ends in .jpg, if it doesn't unset that key
  if(!preg_match("#.jpg$#i",$file))
  {
     unset($the_array($key));
  }
} 

I haven't tested that but I think it should work. That might leave gaps in the array key numbering, so if you want to re-assign the numbers you could use sort($the_array)

[Quaint]

I don't think you should use the above, as it deletes the files in your directory, instead of remove the entries from your array! Be cautious with it!

Instead of

unset($the_array($key)); 

(which deletes the file)

Try writing a line of code that removes the KEY from the ARRAY, don't have much time, but that should be easy to find!

[Jump]

This should work.

 $test_array = Array ('bya_img.inc.php', 'captions.inc.php', 'pic1.jpg', 'pic2.jpg', 'pic3.jpg', 'pic4.jpg', 'pic5.jpg', 'pic6.jpg', 'pic7.jpg', 'Thumbs.db');
  
  foreach($test_array as $file)
  {
      if(strpos($file, '.jpg'))
      {
          $new_array[] = $file;
      }
  }
  
  print_r($new_array); 

[Quaint]

Yup I'd go that way.. Only drawback is that filenames must not have .jpg in their name (for instance: get.jpg.php) but that of course is NOT logical and if you use this in a controlled environment it won't be a problem...

[Kilroy]

foreach($array as $k => $v){
  echo '$v';
} 

That should do the trick If you want spaces in between, or linebreaks, just add those right after the echo '$v' part.

Edit: I assumed you wanted to print this... but if you want to only clean it then the above won't work, sorry.

[Jump]

What I would do ultimately is have a function that worked with any extension.

 $test_array = Array ('bya_img.inc.php', 'captions.inc.php', 'pic1.jpg', 'pic2.jpg', 'pic3.jpg', 'pic4.jpg', 'pic5.jpg', 'pic6.jpg', 'pic7.jpg', 'Thumbs.db');
  
  function grab_images($array, $ext)
  {
      foreach($array as $file)
      {
          if(strpos($file, $ext))
          {
              $new_array[] = $file;
          }
      }
      Return $new_array;
  }
  $test_array = grab_images($test_array, '.jpg'); 

[gavwvin]

I don't think you should use the above, as it deletes the files in your directory, instead of remove the entries from your array!

unset() only unsets an variable, unlink() would remove the file

http://www.php.net/unset
http://www.php.net/unlink

[Quaint]

you are right, sorry

[Koobi]

Edit:


Code was edited to type cast $arg to an array

The thing is, you could have a png or a gif file with a JPG extension...
Using getimagesize(), PHP will lookup the IMAGETYPE constant so that you can be sure that the file is a JPG:

<?php
    function arrCleaner($arg = array())
    {
        $arg = (array) $arg;
        foreach($arg as $eachKey => $eachVal)
        {
            $type = getimagesize($eachVal);
            switch($type[2])
            {
                case 2:
                        /* If it's a JPG, do nothing... */
                    break;

                default:
                        /* Else, unset that value */
                        unset($arg[$eachKey]);
                    break;
            }
        }
        return $arg;
    }
?>

Usage:

/* Assume that $myArr contains your list of files */
print_r(@arrCleaner($myArr)); 

Lookup: http://www.php.net/getimagesize/ if the code doesn't make sense to you
Or let me know if you have problems with this function