Ok, see if you can guess the answer to the riddle!
Whoever guesses right first gets to post the next riddle! Only one riddle at a time please!
How do you make "one" disappear?
Add an 'n' in front of it, thus making it... none.
Jason Unger is me.
"Homer no function beer well without"
rip it to shreds
add another one
Me thinks freakysid is right.
I have a good one, but can't post it until i'm first to get another right.
You are presented with ten bags of marbles. Each bag contains around ten or more marbles. You know that one of the bags contains marbles that each weigh 9 grams. All the other bags contain marbles that each weigh 10 grams. Your task is to work out which bag is the one that contains the 9 gram marbles. You have a set of scales. The challenge is you can only use these scales once. Good luck
Yikes! I think I've lost my marbles!
Put all the bags on the scales at once. Then take one bag off at a time, record the reduction in weight, count the marbles in the bag and divide that by the weight reduction?
If not, then I give up!
Yeah, it's Guinness
Can't see myself getting this riddle
Take 1 marble from bag 1, 2 from bag 2, 3 from bag 3... and so on all the way upto 10 from bag ten.
Put them on the scales...
if the combined weight is 549 gramms then it's bag one.
548 = bag 2
547 = bag 3
546 = bag 4
the maths bit:
There will be 55 marbles on the scales
if bag 1 has 9 gramm marbles then there will be:
1 x 9g marble,
54 x 10g marbles (10+9+8+7+6+5+4+3+2 = 54)
(54*10) + 9 = 549g
bag 2 = 9g marbles
2 x 9g marbles,
53 x 10g marbles (10+9+8+7+6+5+4+3+1 = 53)
(53*10)+18 = 548g
Last edited by Drinky; Feb 28, 2001 at 12:17.
Give me a moment to think....
I still don't get the last riddle.
If you have to find the total weight of 549g then you have to use the scales more than once, don't u?