Help needed: Conditional logic to display a 'No Image' icon

[Psmeg]

Hi all,

I've run into a problem that is giving me a bit of a headache. I'm prety new to PHP, but this problem is probably pretty simple to solve.

I'm using DWMX 2004, and parts of my site give the option to upload an image. What I need is a simple way to check to see if the db field is empty and if so display a standard 'No Image' file stored on the server, if not, then display the actual image.

So I was thinking along the lines of a simple script like the following:

 
<?php
if ($row_rsTest['filename']==' ') {
<img src="$row_rsTest['filename'];" />
} else {
<img src="gfx/cog.gif" />
}
?>

Obvioulsy this is giving me an error but I can't put my finger on the error (as I said, I suck at PHP coding. )

Any help would be MUCH appreciated.

Regards

Psmeg

[Gaheris]

Given only this very small piece of code I would guess that this would work

<?php
if (!empty($row_rsTest['filename'])) {
    echo '<img src="',$row_rsTest['filename'],'" />';
} else {
    echo '<img src="gfx/cog.gif" />';
}
?>

[Psmeg]

Lovely, worked like a charm..

Cheers

Psmeg