MySQL Question

**AlexC** · Dec 31, 2000, 16:44

OK - i have a MySQL database called Pages

in it, there are 4 fields...

page
dateadded
text
author

how would i get it so that if i typed in misc.php?page=legal and it would find the record with legal in the page column, and then display the dateadded and author below it

i'm only a beginner...so be nice to me

**qslack** · Dec 31, 2000, 16:54

Something like this, assuming you were already connected:

Code:

if($page == "legal") {
$results = mysql_query("select * from Pages where page = 'legal';");
    while($row = mysql_fetcharray($results) {
        echo "Lalalala $row['page'] is the page title";
}

A bit rusty on my PHP but that's the basic outline.

**James** · Dec 31, 2000, 16:59

I think you need something like this:

Code:

<?php
mysql_connect("server", "user", "pass");
mysql_select_db("db");
if ($page == "legal") {
$query = mysql_query("SELECT * FROM pages WHERE page='$page'");
$record = mysql_fetch_array($query);
echo("<table><tr><td>Page</td><td>" . $record["page"] . "</td></tr><tr>Date</td><td>" . $record["dateadded"] . "</td></tr> --repeat that code for the other things you want to display-- </table>";
}

<edit>
darn I see Quinn beat me to it while i was typing the reply

</edit>

**AlexC** · Jan 1, 2001, 01:05

OK...whats wrong with the code? i get parse error on line 12

Code:

<HTML>
<HEAD>
<TITLE>Title</TITLE>
</HEAD>
<BODY>
<?php
mysql_connect("localhost", "root", "xxxxxxxx");
mysql_select_db("misc");
if ($page == "legal") {
$query = mysql_query("SELECT * FROM page WHERE page='$page'");
$record = mysql_fetch_array($query);
echo("<table><tr><td>Page</td><td>" . $record["pagetext"] . "</td></tr><tr>Date</td><td>" . $record["dateadded"] . "</td></tr></table>";
}
?>
</BODY>
</HTML>

**mad-onion** · Jan 1, 2001, 01:10

Line 12

echo("<table><tr><td>Page</td><td>" . $record["pagetext"] . "</td></tr><tr>Date</td><td>" . $record["dateadded"] . "</td></tr></table>";

should read

echo "<table><tr><td>Page</td><td>" . $record["pagetext"] . "</td></tr><tr>Date</td><td>" . $record["dateadded"] . "</td></tr></table>";

spot the difference

Hope that helps!

**AlexC** · Jan 1, 2001, 02:14

OK...another problem

i'm designing a content management system now, so that i dont need to upload the files...but i need to add the if (page == $page) (quick guess

) to it to make it show up

i.e if i add misc.php?page=jokes then i need the

Code:

if ($page == "jokes") {
$query = mysql_query("SELECT * FROM page WHERE page='$page'");
$record = mysql_fetch_array($query);
echo "<center><font=verdana><size=2><b>" . $record["pagetext"] . "<br><br>Date Added:" . $record["DateAdded"] . "<br><br>Generated via AtomicEngine 1.1" ;

to be added to the misc.php file

any ideas

also, qslack, james and mad-onion...do you want a mention in my sites credits...this is the engine that powers the whole site and you really are helping!

Alex

**James** · Jan 1, 2001, 03:26

Yes you need to add another if statement for each page you want to display, eg:

Code:

if ($page == "helllo") {
//code for hello page
}
if ($page == "goodbye") {
//code for goodbye page
}

But on your joke example, the code within the if statement needs to be modified as well to display jokes rather than something else. Do you need help with that?

**James** · Jan 1, 2001, 03:46

OK I've just been told that I misunderstood the question

so I'm gonna have another go

Code:

mysql_connect("localhost", "root", "pass");
mysql_select_db("db");
$query = mysql_query("SELECT * FROM page WHERE page='$page'");
$record = mysql_fetch_array($query);
echo "<center><font=verdana><size=2><b>" . $record["pagetext"] . "<br><br>Date Added:" . $record["DateAdded"] . "<br><br>Generated via AtomicEngine 1.1" ;

OK I haven't tested that but it should work. Let me know if there are any parse errors and I'll fix it asap

**AlexC** · Jan 1, 2001, 03:59

ok...error

bear in mind i have it in a template, so its a few lines extra

Fatal error: Call to undefined function: mysql_select() in c:/blds/htdocs/misc.php on line 224

you can also see its a win32 server

**James** · Jan 1, 2001, 04:01

Sorry bout that Alex, mysql_select should be changed to mysql_query.
I've fixed it in my original post as well

(thats what happens when i've stayed up too late for a new years party

)

**AlexC** · Jan 1, 2001, 08:17

hmmm..'nother MySQL question:

Code:

 <?php
else:

mysql_connect("localhost", "root", "oblivion");
mysql_select_db("misc");
mysql_query("INSERT INTO pages(page, Author, DateAdded, pagetext) VALUES ('$page', '$name', 2001020, '$pagetext')")

endif;

?>

all the variables come from a form that is on the same page (hence the else statement)

Alex

Thanx James

**James** · Jan 1, 2001, 08:25

You could do it like this:

Code:

mysql_query("INSERT INTO pages SET page='$page', Author='$author', DateAdded='20001020', pagetext='$pagetext'");

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