Checking that a form value is an integer with php

[backpacklondon.com]

Hi there,

I know this seems a simple question, but I can't pinpoint the reference.

Does anyone know how to check that a user has entered only numbers into a submitted form using php.

The problem is that the form converts the number into a string so that the command 'is_int' does not apply.

What I'm looking for, is probably the php equivalent of the Javascript function:

if (!parseInt(users.cell_number.value, 10)) {

e.t.c......

Thank you very much if you can help.

Regards,

Jason

[gokhana]

what you can do convert value to integer or double whaever you need. Then compare it with the initial value. If they are equal everything is okey. I could not find easier way.


$new = doubleval($org);
if ($org==$new)
return true;
else
return false;

[Kevin Yank]

You could also do it using regular expressions, but the above method looks fairly sound so I'll spare you the code.

[backpacklondon.com]

Thanks gents,

I was hoping there might be a more direct (one function method) as I'm already using something similar:

$test = "0001";
$testcp = $test;
settype($testcp,"integer");


if (strval($testcp) == $test):
echo("$test is a number");
else:
echo ("$test is not a number");
endif;


but clearly not,

Thanks again....

Jason

[freddydoesphp]

Actually what kevin said is the best method here is the code:

function num_check($num) {
return ereg("^[0-9]+$", $num);
}

Sample Usage:
if (!num_check($num)) { print "Must be integer"; }

[backpacklondon.com]

Thank you again Freddy!!!