Find records from one table which exist in another

Hi there, I need your help.

I've got the following two SQL tables (in MySQL):
  • `Phone_number` : number rows 5.340.996
  • `Phone_book` : number rows 24.947

How do I find out which calls were made by people whose phone_number is in the Phone_book?
I tried this query, but as you may have 49.930 rows if in the `Phone_book` if I've 24.947 total rows ?
Any help would be much appreciated.
Code:
SELECT
	FORMAT(
		SUM(top_1000),
		0,
		'de_DE'
	) AS top_1000,
	FORMAT(
		SUM(top_250),
		0,
		'de_DE'
	) AS top_250,
	FORMAT(
		SUM(top_100),
		0,
		'de_DE'
	) AS top_100,
	FORMAT(
		SUM(top_50),
		0,
		'de_DE'
	) AS top_50,
	FORMAT(
		SUM(top_25),
		0,
		'de_DE'
	) AS top_25,
	FORMAT(
		SUM(top_10),
		0,
		'de_DE'
	) AS top_10,
	FORMAT(
		SUM(less_10),
		0,
		'de_DE'
	) AS less_10
FROM
	(
		SELECT
			CASE
		WHEN SUM(taken) / COUNT(u.MonthYear) > 1000 THEN
			1
		ELSE
			0
		END AS top_1000,
		CASE
	WHEN SUM(taken) / COUNT(u.MonthYear) BETWEEN 250
	AND 1000 THEN
		1
	ELSE
		0
	END AS top_250,
	CASE
WHEN SUM(taken) / COUNT(u.MonthYear) BETWEEN 100
AND 249 THEN
	1
ELSE
	0
END AS top_100,
 CASE
WHEN SUM(taken) / COUNT(u.MonthYear) BETWEEN 50
AND 99 THEN
	1
ELSE
	0
END AS top_50,
 CASE
WHEN SUM(taken) / COUNT(u.MonthYear) BETWEEN 25
AND 49 THEN
	1
ELSE
	0
END AS top_25,
 CASE
WHEN SUM(taken) / COUNT(u.MonthYear) BETWEEN 10
AND 24 THEN
	1
ELSE
	0
END AS top_10,
 CASE
WHEN SUM(taken) / COUNT(u.MonthYear) <= 10 THEN
	1
ELSE
	0
END AS less_10
FROM
	Phone_number u
JOIN Phone_book tmp ON (u.phone_number = tmp.phone_number)
GROUP BY
	u.phone_number,
	YEAR (Month)
	) x;


+----------+---------+---------+--------+--------+--------+---------+
| top_1000 | top_250 | top_100 | top_50 | top_25 | top_10 | less_10 |
+----------+---------+---------+--------+--------+--------+---------+
| 49.930   | 1.467   | 254     | 104    | 73     | 84     | 828     |
+----------+---------+---------+--------+--------+--------+---------+
1 row in set

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