TOP 100 script - PHP & MySQL

[AJ]

Hi.
I am trying to make a 'TOP 100' keywords script for my search engine, which launches in a few months.
I have a system in PHP + MySQL which logs all teh keywords that have been searched for, and adds to their popularity every time they are searched for.

Now, I would like to display a 'TOP 100' which allows users to scroll through all the top searches, ordered by popularity.
This is easy enough, as it is just a matter of limiting it to 100, and 'ORDER BY' popularity. I can do that easily.
But what I would like to do, is display a sort of results page menu:

1-19 20-39 40-59 60-79 80-100

I can do a page system easily, with values of Page 1, Page 2, Page 3, Page 4 etc...
But I would like to know how to produce the correct numbers i.e. 1-19, using the least code possible.

What I have so far is: (it probably needs scraping, I haven't been doing PHP for long, and it shows )

<table>
<?php
mysql_connect("localhost", "root", "");
mysql_select_db("eliter");

$limit = 20; 
$numrows = 100;

if (!isset($offset)) $offset=0; 

$result = mysql_query("SELECT * FROM keywords ORDER BY popularity DESC LIMIT $offset, $limit");

echo("<tr><td>");

while ( $details = mysql_fetch_array($result) ) {

$keyword = $details["keywords"];

echo("
<font class=twelvept><b>$num.</b> <a href='http://www.eliter.com/servlet/search?query=$keyword&where=web'>$keyword</a></font><br>
");
}

if ($numrows > $limit) { 
// calculate number of pages needing links 
$pages=intval($numrows/$limit); 
// $pages now contains int of pages needed unless there is a remainder from division 
if ($numrows%$limit) { 
// has remainder so add one page 
$pages++; 
} 
print '<br><font class=tenpt>Top 100 Keywords:&nbsp;&nbsp;'; 

//Create the links 

for ($i=1; $i <= $pages; $i++) { // loop thru 
$newoffset=$limit*($i-1);

if ($newoffset != $offset) { 
printf('&nbsp;<a href="%s?offset=%s">%s</a>&nbsp;', $PHP_SELF, $newoffset, $i, "</font>"); 

} else { 
$lastresult=($newoffset-1)+$limit;
$firstresult = $lastresult-19;
print "&nbsp;<font class=tenptbold> $firstresult  - $lastresult </font>";

}
}
} 
?>

</table>

You can see how I have tried..
Also, what I am having a problem with, is giving each result a number according to where they are in the top 100.
I tried the for statement, but couldn't get it to work with the while statement.
CAn anyone offer any help?

Thank alot.
AJ

[AJ]

Someone? Please?!!

Kevin Yank?
Anyone!!!

I really need some help on this asap
Cheers.

-aJ