I had the code below which allowed me to have 5 pics and when one is clicked it swapped with the main image, so you could move the 5 images around, 4 being thumbnails and 1 main image. It works fine, but I had to change it so that it didnt interfear with a history back button I had.

But this is the image swap code:

http://www.room-check.com/

Code:
<script type="text/javascript">
/*<![CDATA[*/
function Swap(obj,id){
 var main=document.getElementById(id).getElementsByTagName('IMG')[0],msrc=main.src,obj=obj.getElementsByTagName('IMG')[0],tsrc=obj.src;
 main.src=tsrc;
 obj.src=msrc;
 return false;
}
/*]]>*/
</script>

<div id="imgHolder">
<div id="hotel_Pic_Area_Middle">
<img class="HomeFeaturedImages3" src="/foxglove<?=$rows['Foto1_Hot']?>" alt="" border="0" height="362" width="533" />
</div>
</div>
<div id="hotel_Pic_Area_Right">
<div id="imgThumbs">
<div id="hotel_Pic_Area_Right_Pic_1">
<a href="#" class="showImg active" onmouseup="return Swap(this,'imgHolder');" >
<img class="HomeFeaturedImages3" src="/foxglove<?=$rows['Foto2_Hot']?>" alt="" border="0" height="119" width="179" />
</a>
</div>
<div id="hotel_Pic_Area_Right_Pic_2">
<a href="#" class="showImg" onmouseup="return Swap(this,'imgHolder');">
<img class="HomeFeaturedImages3" src="/foxglove<?=$rows['Foto3_Hot']?>" alt="" border="0" height="119" width="179" />
</a>
</div>
<div id="hotel_Pic_Area_Right_Pic_3">
<a href="#" class="showImg" onmouseup="return Swap(this,'imgHolder');">
<img class="HomeFeaturedImages3" src="/foxglove<?=$rows['Foto4_Hot']?>" alt="" border="0" height="118" width="179" />
</a>
</div>
</div>
</div>
Then had to change it to the code below, and basically the images dont swap anymore, so once the first thumb is clicked it takes over the main image, and then that mainimage is lost, with only the 4 thumbnails to play with.

http://devchecksafetyfirst.csf.dcman...otel_ID=247065

Code:
<script>
$(document).ready(function(){
    var mainImage = $("#imgHolder img")[0];
    $("a.showImg").click(function(e){
        e.preventDefault();
        mainImage.src = $(this).children('img')[0].src;
    });
});
</script>

<div id="images_gallery">

<div id="imgHolder">
<div id="hotel_Pic_Area_Middle">
<img class="HomeFeaturedImages3" src="<?=$f['Foto1_Hot']?>" alt="" border="0" height="285" width="430" />
</div>
</div>

<div id="hotel_Pic_Area_Right">
<div id="imgThumbs">
<div id="hotel_Pic_Area_Right_Pic_1">
<a href="#" class="showImg">
<img class="HomeFeaturedImages4" src="<?=$f['Foto2_Hot']?>" alt="" border="0" height="65" width="130" />
</a>
</div>
<div id="hotel_Pic_Area_Right_Pic_2">
<a href="#" class="showImg">
<img class="HomeFeaturedImages4" src="<?=$f['Foto3_Hot']?>" alt="" border="0" height="65" width="130" />
</a>
</div>
<div id="hotel_Pic_Area_Right_Pic_3">
<a href="#" class="showImg">
<img class="HomeFeaturedImages4" src="<?=$f['Foto4_Hot']?>" alt="" border="0" height="65" width="130" />
</a>
</div>
<div id="hotel_Pic_Area_Right_Pic_4">
<a href="#" class="showImg">
<img class="HomeFeaturedImages4" src="<?=$f['Foto5_Hot']?>" alt="" border="0" height="65" width="130" />
</a>
</div>

</div>
</div>
So what I would like to do is go back to the swap way but not have it so the page refreshes, is that possible.