PHP Quiz

[samsm]

the second define should be

define('SS', 'c', 0); 

Arg!

Ok, I forgot about the freaking C constant.

define('S' . strtoupper(str_rot13(f)), 'c', 0);
/*
01234567890123
fghijklmnopqrs
strtoupper to S
SS, 'c', 0
*/ 

You made another obvious mistake, however you've simplified it so much i'm not sure why you stopped, being so close and all....

I wonder what that was. Still don't see it. I'm redoing what I had, so maybe I'll spot it.

[samsm]

Still don't see the mistake. Oh well.

define('C', 'f');
define('SS', 'c', 0);
$d = '2.';
$q = 'S';
// list ($x, $y) = array('p', 'gg');
$x = 'p';
$y = 'gg';

// $b = substr(str_rot13('a'.$x.'xy'.$y), 1, -4);
/*
apxygg ==  'a'.$x.'xy'.$y
nckltt == str_rot13('apxygg')
(there's a table on the php.net str_rot13 
man page that helps with these)

$b = 'c' == substr('nckltt', 1, -4)
*/

$e = 'a';
$f = 63;
$c = 'a' . 12.5 . 63;

${'a1'.${((${'h'} = SS) ? ++$h : 0)}.'5'.(($g = 126 / 5) + ($g * 1.5))} = (float) ($d . ($f * 1.9047619047619));
$a = ${${$b}};
ob_start();
var_dump(${$e});
eval('${S'.$q.'} = substr(strrchr(ob_get_contents(), substr(\'(\',0)), 1, -(int) substr($c, 2, -2)) . round(floor($$b));');
ob_end_clean();
echo $$b; 

[Jeff Lange]

$c = ($e = 'a') . (25 / 2) . ($f = 22 | 45);

how are you getting $c = 1 ....

[samsm]

I don't know why but I was thinking that an assignment would return 1 upon success. Doesn't make much sense upon reflection. Fixed it now, in the code above.

[peanuts]

Since nobody is asking and I have a problem I can't seem to fix easily... I wanted to ask you guru types this:

I want to know at the bottom of my pages how long php took to parse ...

How do I do this with as little code possible???

[Technosailor]

<?php
//at top of page
$start = microtime();
.
.
.
//at end of page
$end = microtime();
$timeelapsed = date('i:s',($end - $start));
?>

[Jeff Lange]

Just a note, someone has to answer the last question before a new question can be asked, but we'll let you off this time

[Technosailor]

sorry...thought it was already answered.

[Jeff Lange]

yeah that was supposed to be quoting the person who posted the question, not you, but whatever, lol, forgot to check the 'Quote Message in Reply?' checkbox.

[peanuts]

Just a note, someone has to answer the last question before a new question can be asked, but we'll let you off this time [img]images/smilies/wink.gif[/img]

Yeah I thoughed it was anserwed too..
Just shows I do find it interesting but It's out of my leage [img]images/smilies/rolleyes.gif[/img]

[Azmo]

I spent some time on the previous question (I thought it should be possible to find an easy solution using serialization and/or regex's). After a while I noticed you don't need to array_flip() function...

foreach(array_reverse(array('Apple'=>'Jobs','Microsoft'=>'Gates','Oracle'=>'Ellison','Sun'=>'McNealy'))as$k=>$c)$n[strtolower(strrev($c))]=strtolower(strrev($k)); 

An alternative solution using array_pop():

for($s=array('Apple'=>'Jobs','Microsoft'=>'Gates','Oracle'=>'Ellison','Sun'=>'McNealy');$k=end($s);array_pop($s))$n[strtolower(strrev($k))]=strtolower(strrev(key($s))); 

I'll post my solution to cyborg's question later today, unless someone else is still trying to solve it... (it's not extremely hard if you use the php manual)

[samsm]

I'll post my solution to cyborg's question later today, unless someone else is still trying to solve it... (it's not extremely hard if you use the php manual)

Go ahead (as far as I'm concerned, at least)!
I'm lacking ambition.

Good modification of the Apple=> Jobs puzzle, by the way.

Post another puzzle when you post the cyborg solution!

[Azmo]

Well, here it is...

/*** CODE ***/ == original code
// COMMENT == refactoring

define('C', 'f');

/*** define('S' . strtoupper(str_rot13(C)), 'c', 0); ***/
// str_rot13(C) == str_rot13('f') == 's'
// strtoupper('s') == 'S'
define('SS', 'c', 0);
$d = '2.';
$q = 'S';

/*** list ($x, $y) = array('p', 'gg'); ***/
$x = 'p';
$y = 'gg';

/*** $b = substr(str_rot13('a'.$x.'xy'.$y), 1, -4); ***/
// str_rot13('apxygg') == 'nckltt'
// substr('nckltt', 1, -4) == 'c'
$b = 'c';

/*** $c = ($e = 'a') . (25 / 2) . ($f = 22 | 45); ***/
// 22 | 45 == 63
$e = 'a';
$c = 'a12.563';

/*** ${'a1'.${((${'h'} = SS) ? ++$h : 0)}.'5'.(($g = 126 / 5) + ($g * 1.5))} = (float) ($d . ($f * 1.9047619047619)); ***/
// ((${'h'} = SS) ? ++$h : 0)
// $h = SS returns 'c', which isn't FALSE, so we increment $h by one, making it 'd'.
// Using ++$h means the if statement returns 'd', not 'c'.
$h = 'd';
// (($g = 126 / 5) + ($g * 1.5)) == 25.2 + 37.8 == 63
// ${'a1'.${'d'}.'5'. 63} == $a12.563
// $d . ($f * 1.9047619047619) == '2.' . 120 == '2.120'
// (float) 2.120 == (float) 2.12
$g = 25.2;
${'a12.563'} = (float) 2.12;

/*** $a = ${${$b}}; ***/
// ${$b} == $c
// ${$c} == ${'a12.563'}
$a = ${'a12.563'};

ob_start();

/*** var_dump(${$e}); ***/
// ${$e} == $a
var_dump($a); // Stores "float(2.12) " in the output buffer (note the ending space).

/*** eval('${S'.$q.'} = substr(strrchr(ob_get_contents(), substr(\'(\',0)), 1, -(int) substr($c, 2, -2)) . round(floor($$b));'); ***/
// '${S'.$q.'}' == '${SS}' == '$c'
// ob_get_contents() == "float(2.12) "
// 'substr(\'(\',0)' == '\'('\'
// 'strrchr("float(2.12) ", \'(\' )' == '"(2.12) "'
// '-(int) substr($c, 2, -2)' == '-(int) substr("a12.563", 2, -2 )' == '-2'
// 'round(floor($$b))' == 'round(floor($c))' == 'round(floor("a12.563"))' == '"0"'
eval('$c = substr("(2.12) ", 1, -2) . "0";');

ob_end_clean(); // Discards the output buffer's contents.

/*** echo $$b; ***/
echo $c; 

So the answer is '2.120'.

Someone else can post the next question, I'm all done PHPing for a while.

[Jeff Lange]

Good work

[lupulet]

Does anyone know where i could find php quizzes and/or tests?

I must hire a php programmer and i want to give some written tests...

Thx.

[MilchstrabeStern]

I am bumping this because i think it is an excellent thread. Just reading the first 4 pages of it has provided me with ideas and concepts I wan't even aware of.

Good stuff!

[sumaira120]

Salam to all

<?php

$i = 'Z';
echo ++$i;

?>


regarding above example ... i am little confused ... wht result is AA

if there is value

$i = 'Y';

then result will be Z not ZZ ??

may be its simple but i didnt understand it ??

Any help ???

Reagrds

[mmarif4u]

W Salam sumaira120
As to think on ur question i am also confused.
but one thing in my mind that loop or incremented z runs two times
to ending the alphabathic series then jump to single A..
This is my assupmtion may be some people not agree or may i am
wrong.
Thanks
ARIF.

[brent5392]

Salam to all

<?php

$i = 'Z';
echo ++$i;

?>


regarding above example ... i am little confused ... wht result is AA

if there is value

$i = 'Y';

then result will be Z not ZZ ??

may be its simple but i didnt understand it ??

Any help ???

Reagrds

Z goes to to AA. AZ goes to BA. BZ goes to CA... etc.

Think of it as numbers, but instead of 0-9 you have A-Z.