Pass multiple ids from product page to cart page

hi all

at present i am adding single product to cart via href

PHP Code:

---

<?
<a href="cart.php?product_id=1"><img src="addtocart.gif"></a>
?>

---

now i want to add "product 1" + "related_products with checkboxes" if their checkboxes are checked.

PHP Code:

---

<input type="checkbox" value="2" name="related[]" />
<input type="checkbox" value="3" name="related[]" />
<input type="submit" value="addtocart"> 


---

i can get checkboxes values in array()

PHP Code:

---

<?
$related_all = array();
$related_all = $_REQUEST['related'];
?>

---

how will i pass all these 3 values to cart.php and what will my below insert code be changed to

PHP Code:

---

<?
if(isset($_REQUEST['product_id']))
{
    $qry = "Insert into cart_table"
}
?>

---

vineet

hi tried this but it outputs id as Array

PHP Code:

---

$related_all = array();
$related_all = $_REQUEST['related'];

foreach($_REQUEST['related'] as $product_id)
{


    if(isset($_REQUEST['related']))
    {
    $id=$_REQUEST['related'];

    echo $id; /* ouput as ArrayArrayArray */
    
    $qry = "select * from product_table where product_id = $id";
    
echo $qry; /* output = where product_id = Array */

    }
}
?> 


---

vineet

$_REQUEST['related'] is not a simple single-dimensional array of values as you might think. Put this into your php code:

PHP Code:

---

print_r($_REQUEST['related']); 


---

then check some checkboxes and test it. View page source and it will become obvious to you what needs to be corrected.

ok i got it working

but dont know why this error is being displayed

Code:

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Warning: Invalid argument supplied for foreach() in F:\xampp\htdocs

---

vineet

Quote:

---

Originally Posted by vinpkl

ok i got it working

but dont know why this error is being displayed

Code:

---

Warning: Invalid argument supplied for foreach() in F:\xampp\htdocs

---

vineet

---

You many need to move your...

Code:

---

if ( isset($_REQUEST['related']) )

---

... ABOVE your foreach. If no boxes were checked, the "foreach" will be trying to work on something that isn't set - and thus isn't an array.

I think that's right. HTH.

Jeff Cohan