Error in a class

Hi Guys,

i'm using this class from here:

http://www.iepak.com/30/topicdetail.aspx

i'm having a few errors with it, i know the public bit is wrong but when i take it away it still doesn't work and ideas on what could be the problem?

PHP Code:

---

<?php
Public Class Media_handler
{
function Convert_Media($filename, $rootpath, $inputpath, $outputpath, $width, $height, $bitrate, $samplingrate)
{
var $outfile = "";
// root directory path, where FFMPEG folder exist in your application.
var $rPath = $rootpath."\ffmpeg";
// which shows FFMPEG folder exist on the root.
// Set Media Size that is width and hieght
var $size = $width."x".$height;
// remove origination extension from file adn add .flv extension, becuase we must give output file name to ffmpeg command.
$outfile =$filename;

// Media Size
$size  = Width & "x" & Height;

// remove origination extenstion from file and add .flv extension , becuase we must give output filename to ffmpeg command.

$outfile = 'out_file.flv';
// Use exec command to access command prompt to execute the following FFMPEG Command and convert video to flv format. 

// exec('command',output array,int return value)

$command = '/C'._rootpath."\ffmpeg -i "\".$inputpath."\".$filename. " -acodec mp3 -ar " .$samplingrate." -ab ".$bitrate."
-f flv -s ".$size." ".$outputpath."\".outfile;

// return output file name for other operations 
Return $outfile;
}

function set_buffering($filename,$rootpath,$path)

{
// root directory path
$_rootPath = rootpath."\flvtool"


// Execute FLV TOOL command also on exec , you can also use other tool for executing command prompt commands. 


// exec('command',output array,int return value)

$command = "/C".$_rootpath."\flvtool2 - U".Path;

// Execute this command to set buffering for FLV 
} 

<!-- This function is used to Grab Thumbnail Image from Generated Flv files , to be display on the list, Note that, FFMPEG can create thumbnail only from FLV Files.. --> 


function($filename, $rootpath, $inputpath,$outputpath, $no_of_thumbs, $frame_number, $image_format, $width, $height)
{
// root directory path
$_rootpath = rootpath."\ffmpeg";
// Media Size
$size = width. "x".height;

// I am using static image, you can dynamic it with your own choice. 
$outfile = "sample.png"; 

// exec('command',output array,int return value)

$command = "/C".$_rootpath."\ffmpeg -y -i " .$inputpath."\".filename." -vframes ".$no_of_thumbs." -ss 00:00:03 -an -vcodec ". $image_format." -f rawvideo -s ".$size. " ". $outputpath."\".$outfile;

// Execute this command using exec command or any other tool to grab image from converted flv file. 

Return $outfile;
}
}

---

thanks guys

Graham

What version of php are you using? If the class was written for php5 it might use functions that aren't available in php4

HI Praetor,

my server and localhost have the latest PHP 5.

cheers

Graham

Hi Graham, there is a parse error on one of the lines:

PHP Code:

---

$command = '/C'._rootpath."\ffmpeg -i "".$inputpath."".$filename. " -acodec mp3 -ar " .$samplingrate." -ab ".$bitrate." 
-f flv -s ".$size." ".$outputpath."".outfile; 


---

should be:

PHP Code:

---

$command = '/C'._rootpath."\ffmpeg -i ".$inputpath."".$filename. " -acodec mp3 -ar " .$samplingrate." -ab ".$bitrate." 
-f flv -s ".$size." ".$outputpath.outfile; 


---

try that.

Hi SpikeZ,

thanks for the help mate i ammedned the code like you said here it is in full:

PHP Code:

---

<?php
Public Class Media_handler
{
function Convert_Media($filename, $rootpath, $inputpath, $outputpath, $width, $height, $bitrate, $samplingrate)
{
var $outfile = "";
// root directory path, where FFMPEG folder exist in your application.
var $rPath = $rootpath."\ffmpeg";
// which shows FFMPEG folder exist on the root.
// Set Media Size that is width and hieght
var $size = $width."x".$height;
// remove origination extension from file adn add .flv extension, becuase we must give output file name to ffmpeg command.
$outfile =$filename;

// Media Size
$size  = Width & "x" & Height;

// remove origination extenstion from file and add .flv extension , becuase we must give output filename to ffmpeg command.

$outfile = 'out_file.flv';
// Use exec command to access command prompt to execute the following FFMPEG Command and convert video to flv format. 

// exec('command',output array,int return value)

$command = '/C'._rootpath."\ffmpeg -i ".$inputpath."".$filename. " -acodec mp3 -ar " .$samplingrate." -ab ".$bitrate." -f flv -s ".$size." ".$outputpath.outfile; 

// return output file name for other operations 
Return $outfile;
}

function set_buffering($filename,$rootpath,$path)

{
// root directory path
$_rootPath = rootpath."\flvtool"


// Execute FLV TOOL command also on exec , you can also use other tool for executing command prompt commands. 


// exec('command',output array,int return value)

$command = "/C".$_rootpath."\flvtool2 - U".Path;

// Execute this command to set buffering for FLV 
} 

<!-- This function is used to Grab Thumbnail Image from Generated Flv files , to be display on the list, Note that, FFMPEG can create thumbnail only from FLV Files.. --> 


function($filename, $rootpath, $inputpath,$outputpath, $no_of_thumbs, $frame_number, $image_format, $width, $height)
{
// root directory path
$_rootpath = rootpath."\ffmpeg";
// Media Size
$size = width. "x".height;

// I am using static image, you can dynamic it with your own choice. 
$outfile = "sample.png"; 

// exec('command',output array,int return value)

$command = "/C".$_rootpath."\ffmpeg -y -i " .$inputpath."\".filename." -vframes ".$no_of_thumbs." -ss 00:00:03 -an -vcodec ". $image_format." -f rawvideo -s ".$size. " ". $outputpath."\".$outfile;

// Execute this command using exec command or any other tool to grab image from converted flv file. 

Return $outfile;
}
}

---

it does not seem to get past line 2 it says:

Parse error: syntax error, unexpected T_PUBLIC on line 2

it's the same on my server and on localhost any ideas on what th eproblem could be?

thanks guys

Graham

i think thats because functions can be public NOT classes themselves. i havent made the jump to php5 yet so havent explored the public,private etc but I am pretty sure it's that......ish

Code:

---

Public class...

---

is invalid public, private, protected go onto the methods and vars only.

You have a lot more problems with this code as well. vars missing there var/access prefix

Ummm scratch this...its all ****ed up....excuse me language...

lol not all mate, the guy before the PHP turorial did one for ASP, i don't think he fully changed the code over to php lol

PLUS im on shared hosting, and due to further reading have found out i need ffmpg installed on the server (shared don't do it they say)

ill need to scrap this idea for now

thanks for the input though guys

Graham