breaking info from database into multiple pages

So I'm pulling information from a database. One of the fields, the interview field is rather long on some entries, so I want to break it down into multiple pages. It was suggested to me that I enter in [pagebreak] in the database field where I want the article to break at, so that I can ensure that it doesn't break mid sentence. This code is broken into 3 parts as I'm showing below. It's not currently working, it's breaking on this line:

function page_url(page) {

with the error: Parse error: syntax error, unexpected T_STRING, expecting ')'

In addition to that can you guys let me know if this set up looks good? Thanks! :)

PHP Code:

---

<?php
$page_break = "[pagebreak]";

// Default is page 1
$page = 1;

// Set the page we're currently on
if(isset($_GET["page"])) {
        $page = $_GET["page"];
}

// Get our article body out of the database
$article_body = "This is page 1 of my article. [pagebreak] This is where page 2 of my article is.";

// Split our article into pages
$article_pages = str_split($article_body, $page_break);
?>

---

PHP Code:

---

<?php 
        // Display our page
        print($article_pages[$page - 1]); 
?>

<?php
        function page_url(page) {
                return "tvinterview.php?id=".$_GET["id"]."&page=".page;
        }

        $previous_link = "";
        $next_link = "";
        
        if($page > 1) {
                previous_page = $page - 1;
                $previous_link = page_url(previous_page);
        }
        
        if($page < count($article_pages)) {
                next_page = $page + 1;
                $next_link = page_url(next_page);
        }
?>

---

PHP Code:

---

<ul class="page-navigation">
<!-- Previous Link -->
<?php if($previous_link == "") { ?>
        <li>Previous</li>
<?php } else { ?>
        <li><a href="<?php print($previous_link); ?>">Previous</a></li>
<?php } ?>

<!-- Numbered Links -->
<?php foreach($article_pages as $index => $page_body) { ?>
        <?php if($page == $index + 1) ?>
                <li><?php print($index + 1) ?></li>
        <?php } else { ?>
                <li><a href="<?php print(page_url($index + 1)); ?>"><?php print($index + 1); ?></a></li>
        <?php } ?>
<?php } ?>

<!-- Next Link -->
<?php if($next_link == "") { ?>
        <li>Next</li>
<?php } else { ?>
        <li><a href="<?php print($next_link); ?>">Next</a></li>
<?php } ?>
</ul>

---

The function str_split() splits the string by character and second your second argument is wrong. and in your case str_split() function is not the suitable function though. Just replace your str_split() to only split() or preg_split() then your code must work though I am not sure about your whole code since i have not tested it yet.

I switched out str_split() to split() and I'm still getting the same error. Any other thoughts?

I'm still a bit of a novice, I appreciate any help you can offer!

Change this line:

PHP Code:

---

$article_pages = str_split($article_body, $page_break); 


---

To

PHP Code:

---

$article_pages = split($page_break,$article_body); 


---

Since the split() function gets the arguments as first pattern and second string and splits the string with the matched pattern and stores the values into the array. and here is $article_pages is your array.

I edited the line, still getting the:

Parse error: syntax error, unexpected T_STRING, expecting ')'

It's still in the same place.

Hi Emma,

Basically you are missing some $ signs off variables

PHP Code:

---


<?php 
        // Display our page 
        print($article_pages[$page - 1]); 
?> 

<?php 
        function page_url($page) { 
                return "tvinterview.php?id=".$_GET["id"]."&page=".$page; 
        } 

        $previous_link = ""; 
        $next_link = ""; 
         
        if($page > 1) { 
                $previous_page = $page - 1; 
                $previous_link = page_url($previous_page); 
        } 
         
        if($page < count($article_pages)) { 
                $next_page = $page + 1; 
                $next_link = page_url($next_page); 
        } 
?>

---

Try that

That moves my error to here:

<?php } else { ?>

at the end, and gives me this:

Parse error: syntax error, unexpected T_ELSE

Thanks again for your assistance, I really appreciate it :)

try

PHP Code:

---

<ul class="page-navigation"> 
<!-- Previous Link --> 
<?php if($previous_link == "") { ?> 
        <li>Previous</li> 
<?php } else { ?> 
        <li><a href="<?php print($previous_link); ?>">Previous</a></li> 
<?php } ?> 

<!-- Numbered Links --> 
<?php foreach($article_pages as $index => $page_body) { ?> 
        <?php if($page == $index + 1); ?> 
                <li><?php print($index + 1); ?></li> 
        <?php } else { ?> 
                <li><a href="<?php print(page_url($index + 1)); ?>"><?php print($index + 1); ?></a></li> 
        <?php } ?> 
<?php } ?> 

<!-- Next Link --> 
<?php if($next_link == "") { ?> 
        <li>Next</li> 
<?php } else { ?> 
        <li><a href="<?php print($next_link); ?>">Next</a></li> 
<?php } ?> 
</ul>

---

:)

Still getting the same error in the same place :(

try ECHOing the RETURNed value...

sometimes, what looks valid to our eyes, comes up bad to the compiler/interpreter... lol...

What value should I echo? None of the page is currently show so should I just take out the code and echo certain values? If so which ones?

thanks :)

Can you paste the full error code as well Emma and the script in full?

Quote:

---

Originally Posted by Emma

What value should I echo? None of the page is currently show so should I just take out the code and echo certain values? If so which ones?

thanks :)

---

oops... i missed the part that the error goes in another place.

can i recommend something "smart" someone told here once...

avoid jumping and in and out of php mode.

either have all html or all php.

you could easily just ECHOed (for example):

Code:

---

echo ("<li>Next</li>");

---

granted in the grand scheme of life, the time lost or wasted as you jump in and out of php mode is VERY small, to me, it makes reading code a lot easier.

I'm still a novice, but I shall take the jumping in and out code to heart. I didn't know that it was something that was recommended!

Current full code:

PHP Code:

---

<?php
$page_break = "[pagebreak]";

// Default is page 1
$page = 1;

// Set the page we're currently on
if(isset($_GET["page"])) {
        $page = $_GET["page"];
}

// Get our article body out of the database
$article_body = "This is page 1 of my article. [pagebreak] This is where page 2 of my article is.";

// Split our article into pages
$article_pages = split($page_break,$article_body); 


        // Display our page 

        print($article_pages[$page - 1]); 


        function page_url($page) { 

                return "tvinterview.php?id=".$_GET["id"]."&page=".$page; 

        } 



        $previous_link = ""; 

        $next_link = ""; 

         

        if($page > 1) { 

                $previous_page = $page - 1; 

                $previous_link = page_url($previous_page); 

        } 

         

        if($page < count($article_pages)) { 

                $next_page = $page + 1; 

                $next_link = page_url($next_page); 

        } 

?>




<ul class="page-navigation"> 

<!-- Previous Link --> 

<?php if($previous_link == "") { ?> 

        <li>Previous</li> 

<?php } else { ?> 

        <li><a href="<?php print($previous_link); ?>">Previous</a></li> 

<?php } ?> 



<!-- Numbered Links --> 

<?php foreach($article_pages as $index => $page_body) { ?> 

        <?php if($page == $index + 1); ?> 

                <li><?php print($index + 1); ?></li> 

        <?php } else { ?> 

                <li><a href="<?php print(page_url($index + 1)); ?>"><?php print($index + 1); ?></a></li> 

        <?php } ?> 

<?php } ?> 



<!-- Next Link --> 

<?php if($next_link == "") { ?> 

        <li>Next</li> 

<?php } else { ?> 

        <li><a href="<?php print($next_link); ?>">Next</a></li> 

<?php } ?> 

</ul>

---

error:

Parse error: syntax error, unexpected T_ELSE


and that is this line

<?php } else { ?>

Try out this:

PHP Code:

---

<ul class="page-navigation"> 
<!-- Previous Link --> 
<?php if($previous_link == "") { ?> 
        <li>Previous</li> 
<?php } else { ?> 
        <li><a href="<?php print($previous_link); ?>">Previous</a></li> 
<?php } ?> 
<!-- Numbered Links --> 
<?php foreach($article_pages as $index => $page_body) { ?> 
       <?php if($page == $index + 1){ ?> 
                <li><?php print($index + 1); ?></li> 
        <?php } else { ?> 
                <li><a href="<?php print(page_url($index + 1)); ?>"><?php print($index + 1); ?></a></li> 
        <?php } ?> 
<?php } ?> 
<!-- Next Link --> 
<?php if($next_link == "") { ?> 
        <li>Next</li> 
<?php } else { ?> 
        <li><a href="<?php print($next_link); ?>">Next</a></li> 
<?php } ?> 
</ul>

---

thank you :)

My page is showing up now with no errors, but it's still not working right. it's showing the text [pagebreak] inline with the rest of the content where it's supposed to break it into a new page, then at the bottom of everything I have this:

# Previous
# 1
# 2
# 3
# 4
# 5
# 6
# 7
# 8
# 9
# 10
# 11
# 12
# 13
# 14
# 15
# 16
# 17
# 18
# 19
# 20
# 21
# 22
# 23
# 24
# 25
# 26
# 27
# Next

They're all links that lead back to the first page. Here's the current code:

PHP Code:

---

<?php
$page_break = "[pagebreak]";

// Default is page 1
$page = 1;

// Set the page we're currently on
if(isset($_GET["page"])) {
        $page = $_GET["page"];
}

// Get our article body out of the database
$article_body = "This is page 1 of my article. [pagebreak] This is where page 2 of my article is.";

// Split our article into pages
$article_pages = split($page_break,$article_body); 

?>





<?php 

        // Display our page 

        print($article_pages[$page - 1]); 

?> 



<?php 

        function page_url($page) { 

                return "tvinterview.php?id=".$_GET["id"]."&page=".$page; 

        } 



        $previous_link = ""; 

        $next_link = ""; 

         

        if($page > 1) { 

                $previous_page = $page - 1; 

                $previous_link = page_url($previous_page); 

        } 

         

        if($page < count($article_pages)) { 

                $next_page = $page + 1; 

                $next_link = page_url($next_page); 

        } 

?>





<ul class="page-navigation"> 

<!-- Previous Link --> 

<?php if($previous_link == "") { ?> 

        <li>Previous</li> 

<?php } else { ?> 

        <li><a href="<?php print($previous_link); ?>">Previous</a></li> 

<?php } ?> 

<!-- Numbered Links --> 

<?php foreach($article_pages as $index => $page_body) { ?> 

       <?php if($page == $index + 1){ ?> 

                <li><?php print($index + 1); ?></li> 

        <?php } else { ?> 

                <li><a href="<?php print(page_url($index + 1)); ?>"><?php print($index + 1); ?></a></li> 

        <?php } ?> 

<?php } ?> 

<!-- Next Link --> 

<?php if($next_link == "") { ?> 

        <li>Next</li> 

<?php } else { ?> 

        <li><a href="<?php print($next_link); ?>">Next</a></li> 

<?php } ?> 

</ul>

---

Hello i wrote the code for you and well tested too if your requirement is like this:

PHP Code:

---

    $data = "Curabitur bibendum porta sem. Fusce rutrum quam vel ipsum. Donec sem. 
            [PAGE_BREAK]Nulla condimentum justo et ligula. Nam ut ipsum. Aliquam mauris. Nulla malesuada metus egestas ipsum. 
            [PAGE_BREAK]Nam nonummy sem a lacus. In condimentum pharetra est. Duis lacus. Maecenas at tortor et elit ornare sollicitudin.";
    
    $delim = "[PAGE_BREAK]";
    
    if(isset($_GET['page'])){
        $page = $_GET['page'] - 1;
    }else{
        $page = 0;
    }
    
    $pages = split("\[PAGE_BREAK\]", $data);
    echo '<div style="border:1px #000000 inset;width:400px;height:150px;overflow:auto;background-color:#FFFFFF;padding:2px;">';
    if(count($pages) >= 1){
        echo $pages[$page];
    }
    else{
        echo $data;
    }
    echo '</div>';
    echo '<div style="border:1px #000000 inset;width:400px;overflow:auto;background-color:#FFFFFF;padding:2px;">';
    echo "| ";
    for($i = 1; $i <= count($pages); $i++){
        if($i == $_GET['page']){
            echo "$i | ";
        }else{
            echo "<a href=\"./paging.php?page=$i\">$i</a> | ";
        }
    }
    echo '</div>'; 


---

ah, thank you rajug! I modified it a bit for my needs and it works beautifully. :)

Your help is much appreciated!