cleaning out a directory

Another easy one, but I'm learning:

This is my array:

PHP Code:

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print_r ($the_array); 


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and it outputs:
Array ( [0] => bya_img.inc.php [1] => captions.inc.php [2] => pic1.jpg [3] => pic2.jpg [4] => pic3.jpg [5] => pic4.jpg [6] => pic5.jpg [7] => pic6.jpg [8] => pic7.jpg [9] => Thumbs.db )

How can i clean out the array so there's only the images (jpg)?

thanks

PHP Code:

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foreach($the_array as $key=>$file)
{
  //checks $file that it ends in .jpg, if it doesn't unset that key
  if(!preg_match("#.jpg$#i",$file))
  {
     unset($the_array($key));
  }
} 


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I haven't tested that but I think it should work. That might leave gaps in the array key numbering, so if you want to re-assign the numbers you could use sort($the_array)

I don't think you should use the above, as it deletes the files in your directory, instead of remove the entries from your array! Be cautious with it!

Instead of

PHP Code:

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unset($the_array($key)); 


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(which deletes the file)

Try writing a line of code that removes the KEY from the ARRAY, don't have much time, but that should be easy to find!

This should work.

PHP Code:

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 $test_array = Array ('bya_img.inc.php', 'captions.inc.php', 'pic1.jpg', 'pic2.jpg', 'pic3.jpg', 'pic4.jpg', 'pic5.jpg', 'pic6.jpg', 'pic7.jpg', 'Thumbs.db');
  
  foreach($test_array as $file)
  {
      if(strpos($file, '.jpg'))
      {
          $new_array[] = $file;
      }
  }
  
  print_r($new_array); 


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Yup I'd go that way.. Only drawback is that filenames must not have .jpg in their name (for instance: get.jpg.php) but that of course is NOT logical and if you use this in a controlled environment it won't be a problem...

PHP Code:

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foreach($array as $k => $v){
  echo '$v';
} 


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That should do the trick :) If you want spaces in between, or linebreaks, just add those right after the echo '$v' part.

Edit: I assumed you wanted to print this... but if you want to only clean it then the above won't work, sorry.

What I would do ultimately is have a function that worked with any extension.

PHP Code:

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 $test_array = Array ('bya_img.inc.php', 'captions.inc.php', 'pic1.jpg', 'pic2.jpg', 'pic3.jpg', 'pic4.jpg', 'pic5.jpg', 'pic6.jpg', 'pic7.jpg', 'Thumbs.db');
  
  function grab_images($array, $ext)
  {
      foreach($array as $file)
      {
          if(strpos($file, $ext))
          {
              $new_array[] = $file;
          }
      }
      Return $new_array;
  }
  $test_array = grab_images($test_array, '.jpg'); 


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Quote:

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I don't think you should use the above, as it deletes the files in your directory, instead of remove the entries from your array!

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unset() only unsets an variable, unlink() would remove the file

http://www.php.net/unset
http://www.php.net/unlink

you are right, sorry :p

Edit:


Code was edited to type cast $arg to an array

The thing is, you could have a png or a gif file with a JPG extension...
Using getimagesize(), PHP will lookup the IMAGETYPE constant so that you can be sure that the file is a JPG:

PHP Code:

---

<?php
    function arrCleaner($arg = array())
    {
        $arg = (array) $arg;
        foreach($arg as $eachKey => $eachVal)
        {
            $type = getimagesize($eachVal);
            switch($type[2])
            {
                case 2:
                        /* If it's a JPG, do nothing... */
                    break;

                default:
                        /* Else, unset that value */
                        unset($arg[$eachKey]);
                    break;
            }
        }
        return $arg;
    }
?>

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Usage:

PHP Code:

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/* Assume that $myArr contains your list of files */
print_r(@arrCleaner($myArr)); 


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Lookup: http://www.php.net/getimagesize/ if the code doesn't make sense to you :)
Or let me know if you have problems with this function :)